From a9bd7c4939b534a1f7ec990613b28e6d54a36f76 Mon Sep 17 00:00:00 2001
From: wulin <wulin@linzikg.com>
Date: Wed, 18 Nov 2020 20:09:03 +0800
Subject: [PATCH] =?UTF-8?q?=E6=B7=BB=E5=8A=A0=E6=96=87=E6=98=8E=E6=8F=90?=
 =?UTF-8?q?=E7=A4=BA?=
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---
 .../com/lz/modules/app/controller/ResultRecordController.java  | 3 +++
 1 file changed, 3 insertions(+)

diff --git a/src/main/java/com/lz/modules/app/controller/ResultRecordController.java b/src/main/java/com/lz/modules/app/controller/ResultRecordController.java
index 5a2e87c6..d4cc6556 100644
--- a/src/main/java/com/lz/modules/app/controller/ResultRecordController.java
+++ b/src/main/java/com/lz/modules/app/controller/ResultRecordController.java
@@ -429,6 +429,9 @@ public class ResultRecordController extends AbstractController {
             }
             //流程已经到了审批节点，那么判断评分是否为或签，如果是那么只需要返回实际评分的那个人即可，否则全部返回
             List<FlowRecord>  flowRecords = flowRecordService.selectFlowRecordByRecordIdFlowProcess(resultRecord.getId(), ChartFlowType.SCORE.getCode());//获取当前的流程节点
+            if(flowRecords.size() == 0){
+                return R.error("绩效流程数据初始化中...，请稍后！");
+            }
             if(flowRecords.get(0).getType().intValue() == 1){
                 //或签,这里还有优化。多个评分节点时，针对每个节点是否为或签
                 isOrScore = true;